What is the value of the hypotenuse of an isosceles triangle with a perimeter equal to 16 + 16√2?

If it is a right triangle with side s, the perimeter will be s(2 + sqrt(2)). Move a factor of sqrt(2) out of the parenthesized expression and get the perimeter as s(sqrt(2)(sqrt(2) + 1) Now let s = 16/sqrt(2) and get 16 + 16 sqrt(2) = 16(sqrt(2) + 1). Which checks. BUT, the triangle does not have to be a right triangle, and if it isn't, most any other value of hypotenuse could be valid.